1. Fizzbuzz

Algorithms

[Problem]

Write a function that takes an integer and returns an array [A, B, C], where A is the number of multiples of 3 (but not 5) below the given integer, B is the number of multiples of 5 (but not 3) below the given integer and C is the number of multiples of 3 and 5 below the given integer.

For example, solution(20) should return [5, 2, 1]

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function solution(number){

}


[Algorithms]

  1. Declare variables for the number of multiples below the given integer(3, 5, 15)
  2. Add counts for the number of multiples below the given integer using ‘for’ statement
  3. get an array of the variables


[Solution]

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function solution(number){
  var num3 = 0;
  var num5 = 0;
  var num15 = 0;
  for(var i = 1; i < number; i++) {
    if((i % 3 === 0) && (i % 5 !== 0)) {
      num3 += 1;
    } else if((i % 5 === 0) && (i % 3 !== 0)) {
      num5 += 1;
    } else if(i % 15 === 0) {
      num15 += 1;
    }
  }
  var result = [num3, num5, num15];
  return result;
}


[Best Practice]

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function solution(n) {
  --n;
  const c15 = Math.floor(n / 15);
  const c3 = Math.floor(n / 3) - c15;
  const c5 = Math.floor(n / 5) - c15;
  return [c3, c5, c15];
}


[What I learned]


[Source]

CodeWars - Fizz/Buzz